2026-05-23_00000380|ligand|9YAR

Rana catesbeiana saxiphilin:STX-C13-OBz (co-crystal); X-ray diffraction 2.40Å
Protein #1 853 residues (96% resolved)

MAPTFQTALFFTIISLSFAAPNAKQVRWCAISDLEQKKCNDLVGSCNVPDITLVCVLRSSTEDCMTAIKDGQADAMFLDSGEVYEASKDPYNLKPIIAEPYSSNRDLQKCLKERQQALAKKMIGHYIPQCDEKGNYQPQQCHGSTGHCWCVNAMGEKISGTNTPPGQTRATCERHELPKCLKERQVALGGDEKVLGRFVPQCDEKGNYEPQQFHGSTGYSWCVNAIGEEIAGTKTPPGKIPATCQKHDLVTTCHYAVAMVKKSSAFQFNQLKGKRSCHSGVSKTDGWKALVTVLVEKKLLSWDGPAKESIQRAMSKFFSVSCIPGATQTNLCKQCKGEEGKNCKNSHDEPYYGNYGAFRCLKEDMGDVAFLRSTALSDEHSEVYELLCPDNTRKPLNKYKECNLGTVPAGTVVTRKISDKTEDINNFLMEAQKRQCKLFSSAHGKDLMFDDSTLQLALLSSEVDAFLYLGVKLFHAMKALTGDAHLPSKNKVRWCTINKLEKMKCDDWSAVSGGAIACTEASCPKGCVKQILKGEADAVKLEVQYMYEALMCGLLPAVEEYHNKDDFGPCKTPGSPYTDFGTLRAVALVKKSNKDINWNNIKGKKSCHTGVGDIAGWVIPVSLIRRQNDNSDIDSFFGESCAPGSDTKSNLCKLCIGDPKNSAANTKCSLSDKEAYYGNQGAFRCLVEKGDVAFVPHTVVFENTDGKNPAVWAKNLKSEDFELLCLDGSRAPVSNYKSCKLSGIPPPAIVTREESISDVVRIVANQQSLYGRKGFEKDMFQLFSSNKGNNLLFNDNTQCLITFDRQPKDIMEDYFGKPYYTTVYGASRSAMSSELISACTIKHCSNSLEVLFQ

MAPTFQTALFFTIISLSFAAPNAKQVRWCAISDLEQKKCNDLVGSCNVPDITLVCVLRSSTEDCMTAIKDGQADAMFLDSGEVYEASKDPYNLKPIIAEPYSSNRDLQKCLKERQQALAKKMIGHYIPQCDEKGNYQPQQCHGSTGHCWCVNAMGEKISGTNTPPGQTRATCERHELPKCLKERQVALGGDEKVLGRFVPQCDEKGNYEPQQFHGSTGYSWCVNAIGEEIAGTKTPPGKIPATCQKHDLVTTCHYAVAMVKKSSAFQFNQLKGKRSCHSGVSKTDGWKALVTVLVEKKLLSWDGPAKESIQRAMSKFFSVSCIPGATQTNLCKQCKGEEGKNCKNSHDEPYYGNYGAFRCLKEDMGDVAFLRSTALSDEHSEVYELLCPDNTRKPLNKYKECNLGTVPAGTVVTRKISDKTEDINNFLMEAQKRQCKLFSSAHGKDLMFDDSTLQLALLSSEVDAFLYLGVKLFHAMKALTGDAHLPSKNKVRWCTINKLEKMKCDDWSAVSGGAIACTEASCPKGCVKQILKGEADAVKLEVQYMYEALMCGLLPAVEEYHNKDDFGPCKTPGSPYTDFGTLRAVALVKKSNKDINWNNIKGKKSCHTGVGDIAGWVIPVSLIRRQNDNSDIDSFFGESCAPGSDTKSNLCKLCIGDPKNSAANTKCSLSDKEAYYGNQGAFRCLVEKGDVAFVPHTVVFENTDGKNPAVWAKNLKSEDFELLCLDGSRAPVSNYKSCKLSGIPPPAIVTREESISDVVRIVANQQSLYGRKGFEKDMFQLFSSNKGNNLLFNDNTQCLITFDRQPKDIMEDYFGKPYYTTVYGASRSAMSSELISACTIKHCSNSLEVLFQ
Non polymer #2 A1CTG

InChI=1S/C16H20N6O4/c17-13-20-11-10(8-26-12(23)9-4-2-1-3-5-9)19-14(18)22-7-6-15(24,25)16(11,22)21-13/h1-5,10-11,24-25H,6-8H2,(H2,18,19)(H3,17,20,21)/t10-,11-,16-/m0/s1

[H]/N=C\1/N[C@H]2[C@@H](N/C(=N/[H])/N3[C@]2(N1)C(CC3)(O)O)COC(=O)c4ccccc4
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Reference